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Can someone help out with this problem please. x^2-3x=0 with explanation
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x^2=3x so x^2/x=3 So x=3
How did you get x=3
since x^2-3x =0, x^2=3x
so just arrange x to one side you will get x^2/x=3
divide x^2 by 3x
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or check your answer like this 3^2-(3)(3)=0
I know that the answer is x=3 because it comes out to 9-9=0 but I dont know how you got rid of the x^2 to get x=3
x times x divided by x
Thank you I understand
I can't type square in my system that's why used '^'
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