Question

For what value of the constant "c" is the function "f" continuous on (-∞,∞) where

cy+1 if y<- (-∞,5]
f(y) = {
c(y^2)-1 if y<- (5,∞)

Answer 1

replace \(y\) by 5 in both expressions, set them equal, solve for \(c\)

Answer 2

you get
\[5c+1=25c-1\] as a start

Answer 3

THANK YOU ONCE AGAIN!!!!! :)