Solve the problem. When making a long distance call from a certain pay phone, the first three minutes of a call cost $1.10. After that, each additional minute or portion of a minute of that call costs $0.30. Use an inequality to find the number of minutes one can call long distance for $4.70. A) 15 minutes or fewer B) 4 minutes or fewer C) 12 minutes or fewer D) 16 minutes or fewer
3(x+.30)=4.70?
It says to use an inequality
eww! lol k
From where did you get that formula? Did you make that up?
yeah i like trying to put them together in differn orders not even close huh?
No because you need to basically use graph paper to do this. You need to plot the points (3, 1.10) and (4, 1.40) then use y = mx + b again.
I'm not even going to do anything else. You need to figure this out yourself.
so is the slope-30/1
um no its to hard
Hardly: y = mx + b 1.10 = 3m + b 1.40 = 4m + b b = 1.10 - 3m b = 1.40 - 4m b = b 1.10 - 3m = 1.40 - 4m 4m - 3m = 1.40 - 1.10 m = .30 b = 1.10 - 3m b = 1.10 - 3(.30) b = 1.10 - .90 b = .20 y = .30x + .20
Now we need to find the number of minutes you can call for 4.70. To do that you have to make an inequality
4.70 ≥ .30x + .20 4.70 - .20 ≥ .30x 4.50 ≥ .30x 4.50/.30 ≥ x 15 ≥ x
So 15 min or fewer
You seem to be in disbelief regarding the simplicity of this problem.
no im just extremely exhuasted i know these its just i cant remember Im takinga pretest so i can get in to my midterms at the school. I have 76 math problems. and I need a 70 to pass I took it once and failed so now im here trying to pass it so i can take the darn test
You cannot guess these things. You have to learn the concepts or else you will fail everytime.
i need to know if they are right
i do its just i have a science test to study for to and my children are sick im sick i just want to get it over with
It's not like I have plenty of free time on my hands either. I'm actually taking a break from the work I have to do. I can't do 76 problems.
i know im not asking and i really do appreciate your help
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