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OpenStudy (anonymous):
lets say that we have 10 blue , 12 red and 8 white balls in a box , in how many ways we can choose 3 balls together and 2 of the three are blue ?
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OpenStudy (anonymous):
order dose or dosent matter ?!!
OpenStudy (anonymous):
the possible choose are (2B, 1R), (2B,1P), (3B) so, the sum possible ways are : 10C2*12C1 + 10C2*8C1 + 10C3
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