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Given that (-1,4) is the reflected image of (5,2), find an equation for the line of reflection.
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|dw:1350051840147:dw| we need to find eqn of the mirror.. let intersection point be (x,y) 1st eqn would be equating slopes.. 2nd eqn would be equating distances..
|dw:1350052072581:dw| 1) take any 2 points,, find slope,,equate it to the slope taking other 2 points.. 2)AC = BC 2eqns, 2 variables..solve for intersection point.. now you know the slope of AC slope of line can be calculated since AC is perpendicular to line with slope known and (x,y) known,,eqn can be found out..
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