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how do you sketch the graph of the equation 2x^2-3x
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|dw:1350063445793:dw|
this factories to x(2x - 3) when this = 0 , x=0 and 3/2 so u have the 2 intercepts on the x-axis
its a quadratic so the shape is a parabola and as the coefficient of x^2 is positive it will open upwards and have a minimum value
do u know any calculus?
no, I am currently in pre-calculus and we have been reviewing algebra two. We haven't gotten to actual calc yet
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ok - i asked this because u can use calculus to find the minimum value of the function
Oh, okay. Yeah, we haven't gotten to any of that stuff yet
but the minimum value of x will be 0+ 3/2 / 2 = 0.75
yours a rough sketch
|dw:1350064276332:dw|
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