Question

If sin theta = 1/2 and theta is in Quadrant 1, fins sin 2theta

Answer 1

sin theta= 1/2
sin theta = sin pi/6
theta= pi/6
sin2theta= sin 2pi/6= sinpi/3= (square root of 3)/2

Answer 2

sin 2 theta = 2 sin theta cos theta

cos^2 theta = 1 - sin^2 theta = 1 - (1/2)^2 = 3/4
cos theta = sqrt(3/4) = sqrt3 / 2

so sin 2 theta = 2 * 1/2 * sqrt3 / 2
= sqrt3 / 2

Answer 3

thx

Answer 4

yw