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Jessica attains a height of 4.7 feet above the launch and landing ramps after 1 second. Her initial velocity is 25 feet per second. To find the angle of her launch, which equation can you use with the given information to solve for θ?
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a. Which equation can you use with the given information to solve for ? Equation 2 b. Substitute the known values and solve for . 55.9 c. What is Jessica’s height above the launch and landing ramps after 0.5 second? 6.4 ft d. What distance has Jessica traveled after 1 second
we can use two equation equation2 y(t)=votSin theta-16t^2 (vertical distance) equation 1 x(t)= vorcostheta (horizontal distance)
i mean x(t) votcostheta vo is the feet per square second and t is the time
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