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lim x approaches 0 for 4x+2h-16
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\[ \Large \lim_{x\to0}(4x+2h-16) \]
just plug in x=0
I think I got it This is the derivative so now I must solve for the lim as x approaches 0
Great
My mind went blank for a sec
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i am going to make a guess
that you want the limit as \(h\to 0\) rather than as \(x\to 0\) just a guess, but when you said "derivative" that springs to mind
always helps if you know what the question you're asking is...
inb4 'the answer you gave me was wrong.'
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