Mathematics
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OpenStudy (anonymous):
simplify cubed root 108 please help
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OpenStudy (anonymous):
factor 108
OpenStudy (anonymous):
u can do the factorization of 108 in prime numbers?
OpenStudy (anonymous):
ex 16=2*2*2*2
do the same for 108
OpenStudy (anonymous):
1st factor 108 into primes...did u do that?
OpenStudy (anonymous):
done
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OpenStudy (anonymous):
suppose u have to find cube root of 8
cube root of 8= 8^(1/3)= (2*2*2)^(1/3) =(2^3)^(1/3)= 2
OpenStudy (anonymous):
does it help u?
OpenStudy (anonymous):
108=2*2*3*3*3= 2^2 * 3^3
OpenStudy (anonymous):
so (108)^(1/3) = { 2^2 * 3^3} ^(1/3) = 2^(2/3) *3
OpenStudy (anonymous):
cube root 0f 108= 4^(1/3) * 3
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OpenStudy (anonymous):
express the following surds in its simplest form of cube root of 108
OpenStudy (anonymous):
108^(1/3) = 4^(1/3) * 3
OpenStudy (anonymous):
or 108^(1/3) = 2^(2/3) * 3
OpenStudy (anonymous):
fine?
OpenStudy (anonymous):
:'(
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OpenStudy (anonymous):
why...wat wrong?
OpenStudy (anonymous):
r u 9 th std ? boy
OpenStudy (anonymous):
did u get the answer of ur question?
OpenStudy (anonymous):
understood?
OpenStudy (anonymous):
plz give the explaination if u know
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OpenStudy (anonymous):
108=2*2*3*3*3= 2^2 * 3^3
so (108)^(1/3) = { 2^2 * 3^3} ^(1/3) = 2^(2/3) *3
did u get this?
OpenStudy (anonymous):
u know that power gets multiplied
so(a^p)^(1/q) = (a) ^(p/q)
OpenStudy (anonymous):
and (ab)^n= (a)^n * (b) ^n
OpenStudy (anonymous):
does it make sense?
OpenStudy (anonymous):
108=2*2*3*3*3= 2^2 * 3^3
so (108)^(1/3) = { 2^2 * 3^3} ^(1/3) = 2^(2/3) *3
did u get this?
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OpenStudy (anonymous):
no.....
OpenStudy (anonymous):
ok
1st factor 108 into primes
so start dividing 108 by smallest prime
so 108=2*54
now divide 54 by 2
so 108=2*2*27
............
108= 2*2* 3*3*3
OpenStudy (anonymous):
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