Question

in the figure,

BD = CD
BE= DE
AP=PD
and, DG//CF

find ratio of areas of triangle ADH to ABC.

Answer 1

looks like the other one....

Answer 2

??

Answer 3

Just saying, it reminds me of te //gram question (with the other 2 sides missing)

Answer 4

hmm..

Answer 5

so my opinion :

area triangle ADH = (area triangle ABC)/4 - area triangle DHE

????

Answer 6

yep..that'd be right sir..

Answer 7

My opinion is use AD as base, find the relationship between B and H in triangle ABD.

Answer 8

S=S'

Answer 9

so S' would be 1/6 of ABE=1/6 * A/4=A/24
So AHD=A/4-A/24=5A/24

Answer 10

will you please elaborate the solution ?

Answer 11

that's excellent..thank you again @sauravshakya :)

Answer 12

welcome