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Mathematics 12 Online
OpenStudy (anonymous):

Find an equation of the tangent line to the given curve at the specified point: y=(-2e^x)/x at the point (1,-2e)

OpenStudy (anonymous):

U need a point and a slope

OpenStudy (anonymous):

I think the answer is y= 7.436x-7.436+2e but this is not right

OpenStudy (anonymous):

try changing the last term to -2e

OpenStudy (anonymous):

still not right

OpenStudy (anonymous):

y=-2e

OpenStudy (anonymous):

how did you do that ?

OpenStudy (anonymous):

the slope fr the function is -2e^x (x-1)/x^2....at the given pt the slope is zro

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