Question

if 2x^2-kx+3 = 0 has imaginary roots, what is the value of k?

Answer 1

When Δ < 0

Answer 2

@3psilon Can you continue?

Answer 3

I got that part I don't get finding K

Answer 4

Show me what you got?

Answer 5

Start with Δ = ...?

Answer 6

I got = k^2 +24

Answer 7

-24*

Answer 8

Δ = k² - 24 < 0

Answer 9

Yes but I don't know what to do after that

Answer 10

Suppose k² -24 = 0
=> k = -√ 24 or k = √24
Thus when Δ < 0, -√ 24 < K < √24

Answer 11

I don't get why \[-sqrt{24} <k\] @Chlorophyll

Answer 12

k < | √24 | <=> -√24 < k < √24