Question

I need to convert this to basic SI form: -0.000398*dm^3*h*km^-2.
Wolfram alpha gives -1.433×10^-9 m*s but i keep gettin -10^-9. where do i go wrong?

-0.000398*m^3*10^-3*3600*s*m^-2*10^-6

Answer 1

I'm going to separate the numbers from the units and from the powers of ten first.
(-0.000398)*(3600)*(m^3)*(s)*(m^-2)*(10^-3)*(10^-6)

Answer 2

Multiplying the numbers gives -1.4328
Multiplying the units gives m*s
Multiplying the powers of ten gives 10^-9

Answer 3

Oh, hold up, I missed the original expression . . .
Let me start over.
:">

Answer 4

i did get 1.4328 too at some point but didn't know how to continue from there

Answer 5

-0.000398 = -3.98×10^-4
dm^3 = (m ×10^-1)^3 = m ×10^-3
h = 3.6×10^3 s
km^-2 = (m ×10^3)^-2 = m ×10^-6

Answer 6

Sorry, should be m^3 ×10-3 for the dm^3 and m^-2 ×10^-6 for the km^-2.

Answer 7

OK

= (-3.98)*(3.6)*(m^3)*(m^-2)*(s)*(10^-4)*(10^-3)*(10^3)*(10^-6)

Answer 8

= -14.328 ×10^-10 m*s = -1.4328 ×10^-9 m*s.

Answer 9

thanks! now i get it.