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What's the inverse of 7+x^2+tan(pix/2) ?
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forget it is that really the whole question?
or does it have to do with finding the derivative of the inverse?
That's the start of the question, to find the inverse at x=7
well that is a different question the inverse at \(7\) is 0 because \[7+0^2+\tan(0)=7\]
in other words, \[f(0)=7\] by inspection, therefore \[f^{-1}(7)=0\] by definition of the inverse don't try to find a general formula for it, you will not
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Okay, thanks! Just curious- why could you not find a general formula for it?
try it and see
Fair enough
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