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Is this correct ? Is this final result ?
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no
look at the denominator (2-i)(2+i) = 4 -2i +2i -i^2 = 4 + 1 = 5
as a sanity check, remember that when you mult by the complex conjugate you get a real number.
Thanks Coolsector. Stupid mistake :/ So the result is 4i - 3 right ? Could you write it phi little bit comprehensibly ? I'am not good at english.
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(a-bi)(a+bi) = a^2 + b^2 -> real number
4i - 3 -> correct!
So everytime when i modify complex number with "formula" i should get real number right ? This is my check right ?
everytime you multiply complex with a the corresponding conjugate : (complex) * (conjugate complex) = real number
"a the" should be only "the"
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Ok, i understand it little bit .. Thanks a lot
yw
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