Question

It Takes 1 hour longer to fly to St.Paul at 200 mi/h than it does to return at 250 mi/h . How Far Is St.Paut

( Needs Too Be Solved In Equation Form )

Answer 1

\[v=\frac{ x }{ t }\]

Answer 2

d1 = d2
200 ( t +1) = 250t

Answer 3

\[t=\frac{ x }{ 200 }\]
\[t _{2}=\frac{ x }{ 250 }\]

Answer 4

200t+200=250

Answer 5

\[x/200+1=x/250\]

Answer 6

200t+200=250 t
@Ambbiiee Can you solve for t ?

Answer 7

my logic is not corrct is it @Chlorophyll

Answer 8

200=250
-200 -200
_____________
200t =50

Answer 9

I'm not sure, just see if we come to the same result!

Answer 10

t=4

Answer 11

Now plug back to d1 = 200t

Answer 12

i get it now thankyou !(:

Answer 13

I mean plug it back to 250t => d2 = 1,000 mi