Rationalize the denominator of 5 over quantity of 9 plus square root of 5
quantity of 45 minus 5 square root of 5 over 76
quantity of 45 minus square root of 5 over 76
5 square root of 5 over quantity 9 square root of 5 end root plus 5
5 square root of 5 over 86
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I really have no idea, I listened in class and everything but this one unit is what has me stumped, I understand if you dont want to give me the answer straight out answer but i really dont know what to do.
OpenStudy (anonymous):
( a + b) ( a - b) = a² - b²
( 9 + √5) ( 9 -√5) = ...?
OpenStudy (anonymous):
how do i add to the square root of 5? or even minus it..
OpenStudy (anonymous):
That's where you need to learn the formula to rationalize:
( a + b) ( a - b) = a² - b²
a = 9, b = √5
( 9 + √5) ( 9 -√5) = ...
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OpenStudy (anonymous):
9 |dw:1350179037643:dw|
OpenStudy (anonymous):
imean sqrt 14 and sqrt of 4 ?
OpenStudy (anonymous):
a = 9 --> a² = ...?
b = √5 --->b² = ..?
OpenStudy (anonymous):
does a = 9^2
b = sqrt5^2
?
OpenStudy (anonymous):
Yes, a² = 9² = ...?
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OpenStudy (anonymous):
81
OpenStudy (anonymous):
b² = ...?
OpenStudy (anonymous):
sqrt 25
OpenStudy (anonymous):
b = √5 --->b² = ( √5 )² = 5
OpenStudy (anonymous):
Now a² - b² = ...?
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OpenStudy (anonymous):
i dont know how to subtract that..
OpenStudy (anonymous):
a² - b²
= 81 - ... =
OpenStudy (anonymous):
wait so 5?? 81 x 5?
OpenStudy (anonymous):
a² - b²
= 81 - 5
=
OpenStudy (anonymous):
i mean minus... 76
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OpenStudy (anonymous):
This is denominator:
( a + b) ( a - b) = a² - b² a = 9, b = √5
( 9 + √5) ( 9 -√5) = 81- 5 = 76
OpenStudy (anonymous):
Numerator:
5 ( 9 - √5) = ...?
OpenStudy (anonymous):
32 1/2
OpenStudy (anonymous):
Distribute 5 into the bracket:
5 ( 9 - √5) = 45 - 5√5
OpenStudy (anonymous):
wouldnt that be like 33.something..
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OpenStudy (anonymous):
Now compare my solution with the choices!
OpenStudy (anonymous):
wait the 5(9-sqrt5) one ?
OpenStudy (anonymous):
= ( 45 - 5√5 ) / 76
OpenStudy (anonymous):
answer a. thanks
OpenStudy (anonymous):
NO, it's not!
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OpenStudy (anonymous):
what ?!
OpenStudy (anonymous):
I mean a choice is correct!
About your asking if my solution as same as yours, so it's NOT!