Write the quadratic function in vertex form.

y = x2 - 14x + 53

A. y = (x - 7)2 - 4

B. y = (x + 7)2 - 4

C. y = (x - 7)2 + 4

D. y = (x + 7)2 + 4

Question

Write the quadratic function in vertex form.

y = x2 - 14x + 53

A. y = (x - 7)2 - 4

B. y = (x + 7)2 - 4

C. y = (x - 7)2 + 4

D. y = (x + 7)2 + 4

anonymous · Answer

i cant figure this out..

campbell_st · Answer

rewrite the equation 

y - 53 = x^2 -14x + ?    


you now need to complete the square

anonymous · Answer

what do you mean complete the square? i'm horrible at math..im sorry

campbell_st · Answer

this is a perfect square

$$(x - a)^2 = x^2 - 2ax + a^2$$

you need to halve the middle term... -14 then square it... 

add the value to both sides of the equation... 

thats the process of completing the square...  you are looking to find a so you can calculate a^2

anonymous · Answer

so would the answer be.. 
B. y = (x + 7)2 - 4

campbell_st · Answer

not quite... what is half of -14..?

anonymous · Answer

-7

anonymous · Answer

ohhh..so id be C

campbell_st · Answer

ok... so you will have to add (-7)^2 to both sides

y - 53 + 49 = x^2 - 14x + 49

the write hand side can be written as a perfect square

$$y - 4 = (x - 7)^2$$

all you need to do now is add 4 to both sides

campbell_st · Answer

lol... right hand side... not write hand side... sorry about that

anonymous · Answer

but then what answer choice would that be.. ? bc its cancel out the 4 of the left and its be
y=(x-7)^2+4

so would it be
C. y = (x - 7)2 + 4????

campbell_st · Answer

ok... in the notation for you choices... )2 and )^2 both mean squared...

campbell_st · Answer

and it is C... well done

anonymous · Answer

ok:) thankyou!!