Question

Find the inverse laplace transformation of:

[2(s-1)e^(-2s)] / (s^2 - 2s +2)

I got it to be 2u_2(t) e^t cos(t) but the answer has e^(t-2) cos (t-2). I don't know what I did incorrectly.

Answer 1

Correction: the answer I got was 2u_2(t)*e^(t-1)*cos(t-1)

Answer 2

Oh wait nvm I understand where the 2 is coming from. It's using u_c(t) f(t-c)