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Solve the equation. Give a general formula for all the solutions. 2tan4(θ)=-2√3
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general formula?
oh damn, was that \[2\tan(4x)=-2\sqrt{3}\]? i must be tired same idea though make \[\tan(x)=-\sqrt{3}\] so \(4x=\frac{2\pi}{3}\) and \(x=\frac{\pi}{6}\)
you should get something like \[x=\frac{(3k-1)\pi}{12}\] when you are done finding a few of them and generalizing
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