Help Please, attachments to come...
Here's the question and the solutions i got, but at least one of the answers are wrong, and i don't know which ones...
I'm about to post the work i've done...
B and D are reversed. I think you should try L'Hopital's rule on the third one on the list. sin(2x-2) ------- +1 (x-1) the fraction is indeterminate, s o d/dx top = 2cos(2x-2), eval at 1 = 2 d/dx bottom = 1 BUT don't forget the +1, so the third one is 3, not 2 And the first one is 2, not 3
You forgot the -1 and the +1 that are next to the hard part, that's all. You have very clear work, it is a pleasure to read.
Oh whoop! hahahahahaha! I'm banging my head on the table right now! Thanks so much for your help again! You're the best! :D
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