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Determine the slope and the y-intercept of the graph of the equation. -x + 11y - 33 = 0
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rewrite the term in ax +by = c
\[11y=x+33\]
you'll get the slope if you transform the equation into the slope form which is y = mx + b..y's coefficient must be 1...
the Y coefficient, i mean..
y intercept=3
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\[y=-\frac{ 1 }{ 11 }x+3\]
y=1/11x+3 y=-1x+3
i think it's positive..
it can't be \[-1\div11, \]
the slope would be.. 1/11...
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look, -x + 11y = 33 11y = x + 33 if you divide bot sides by 11, you'll get \[y = \frac{ 1 }{ 11 } + 3\]
1/11 x
forgot to type x
\[y = \frac{ 1 }{ 11 }x + 3\]
y = mx + b m = slope b = y-intercept
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thanks.
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