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X^2<1/100 and x<0; What is the tightest range in which x can lie?
a…-1/10
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a
how u solved it
i take it as x< 0 ok then i found -1/10<x<1/10 then i take -1/10<x<0<1/10 so tighest range is -1/10<x<0 so is ds approach is correct
i want to know exact approach
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