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Triangle ACB is right angled at C. There is a point D on AB such that AD = DB and AC = CD. Find
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draw it
|dw:1350362760889:dw| i think its like this. @sara12345
|dw:1350222434653:dw|
CD = AB/2 = AD = DB = AC
Can you show me your solution, please? :) @sara12345 so, is <A, 60?
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thats right <A = 60
draw two parallel line segments
Can you show me how? :) I just based my answer on your illustration. XD
|dw:1350223028736:dw|
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