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The perimeter of a basketball court is 278 ft. The length is 43 ft longer than the width. Find the dimensions of the court.
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|dw:1350240915228:dw|
since you can express the length in terms of the width with length = width + 43, and since the total perimeter is given: 278 you can plug these into the equation for perimeter to solve for width
so you end up with \[278 = 2w + 2(w+43)\]
can you solve this for w?
I got 48
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good! Now since we know that length = width + 43 we can find the length
91?
yes
thank you sooo much !!
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