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How do you factor the following...
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\[x ^{3}+12x ^{2}+36x\]
here's a hint.. \[\huge x(x^2 + 6x + 6x + 36)\] does that help?
yeap thanks
welcome
remember...you still have to factor out x^2 + 6x + 6x + 36
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x(x+6)^2
right
ok how about this one... x^3-3x^2-4x
break down the middle term again... \[\huge x(x^2 - 4x + x - 4)\]
ok, was not sure how to break that down again...one moment
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x(x-4)(x+1)
right
i have to leave now...so if you have more questions...post it as a new question
ok thanks for the help
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