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MIT 6.189 A Gentle Introduction to Programming Using Python (OCW) 14 Online
OpenStudy (strangefyr):

#MOOC question: which is the correct answer for the initial IDLE practice exercise #3? >>> 23.0**5 6436343.0 >>> 23**0.5 4.795831523312719

OpenStudy (strangefyr):

I also am unsure how to tackle question #4 ...

OpenStudy (strangefyr):

i figured out #3 ... still unsure about #4.

OpenStudy (anonymous):

23**0.5 is 23 to the 1/5th power.... For No 4 just type in the formula at the bottom but substitute a,b,c with the given numbers.

OpenStudy (anonymous):

Isn't 23**0.5 is 23 to the 1/2th power?

OpenStudy (anonymous):

Yes, sorry...:-)

OpenStudy (anonymous):

ie square root

OpenStudy (strangefyr):

Thanks estudier!

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

Aha! So when I needed to do square root I imported math and then did sqrt, but this is much more elegant. I'd forgotten my math, thanks!

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