Question

evaluate f(x)=3sin+3cos1/2x when f(x)=x^2-2

Answer 1

oh i wrote that wrong it is evaluate f(x)=3sin+3cos1/2x at x=pi/3

Answer 2

sorry :(

Answer 3

Ah ok now it makes a little more sense :)
What is the argument of the sine function?

Answer 4

what does that mean

Answer 5

The stuff inside of the function is called the "argument" :)
What is suppose to go inside of the sine function, because you have it empty right now.
You forgot to write something there.

Answer 6

3sin(?)

Answer 7

oh x sorry lol

Answer 8

So you just plug in pi/3 everywhere you see an x in the problem.
What part are you stuck on?
Do you remember your special angles? :D

Answer 9

so is it \[3\sqrt{3}\]

Answer 10

Yayyy good job \c:/