Question

Could anyone help me solve this?

9^-x times 12^x

Answer 1

\[9^{-x} \times 12^{x} = \frac{ 12^x }{ 9^{x} } = (\frac{ 12 }{ 9 })^x\]

Answer 2

12/9 can be simplified further into 4/3

Answer 3

Thank you so much!

Answer 4

Do you know how to do \[\sqrt{3} + \sqrt[2]{2} \div \sqrt{3} - \sqrt[2]{2}\]