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See attached picture. On this I am pretty sure you can pull the 1/2 in front and then make the expression under the radical to the -1/2 and then do the quotent rule inside. But, I am not sure if this process is correct and what it will end up looking like please help
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what do you want? differentiate?
|dw:1350323872453:dw|
du=u' dv=v'
you would put top expression in brackets, and put it to a power of 1/2 you would put the bottom in brackets and put it to the power of 1/2 you would let the top expression be u let the bottom expression be v
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yes so the 9x-6(4)-(4x+6)(9)/(9x-6)^2
|dw:1350324350534:dw| |dw:1350324379948:dw|
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