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OpenStudy (anonymous):
Quadrilateral DEFG is a rectangle. If DE = 14+2x and GF = 4(x-3)+6, find GF.
a. 28
b. 34
c. 38
d. 25
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OpenStudy (anonymous):
OpenStudy (nubeer):
as its rectangle and DE =GF
so,
14+2x =4(x-3) + 6
14+2x = 4x -12 + 6
can u do from now?
OpenStudy (nubeer):
@Lunalovegood
OpenStudy (anonymous):
one second please :)
OpenStudy (nubeer):
sure. :)
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OpenStudy (anonymous):
i think it is d.
OpenStudy (nubeer):
nop.. can u tell me what is the value of x u have found?
OpenStudy (nubeer):
oopps sorry my bad .. let me tell u again.. i think i got soemthing wrong..
OpenStudy (nubeer):
nop... i think its right.. tell me the value of x?
OpenStudy (nubeer):
@Lunalovegood
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OpenStudy (anonymous):
uuummm
OpenStudy (nubeer):
14+2x = 4x -6
20 = 2x ?
OpenStudy (anonymous):
c.? i'm not sure
OpenStudy (nubeer):
hmm nop.. well follow the steps.. first find x
well for me x = 10
put this value of x in GF = 4 (10-3) + 6
OpenStudy (anonymous):
a.
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OpenStudy (nubeer):
4 (10-3)+6
4(7) + 6
28+6
= 34
OpenStudy (anonymous):
oh i see what i did wrong i forgot to add the 6
OpenStudy (nubeer):
lol i see.. well its ok.. jjust do more practice :)
OpenStudy (anonymous):
thanks!!
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