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Mathematics 18 Online
OpenStudy (anonymous):

Factor completely: −2x3 + 6x2 −x(2x2 − 6x) 2x(−x2 + 3x) −2x2(x − 3) Prime

OpenStudy (anonymous):

they ^ after the varibles

OpenStudy (anonymous):

what will be a common factor between the two terms

OpenStudy (anonymous):

2?

OpenStudy (anonymous):

2 alone?

OpenStudy (anonymous):

2x i think

OpenStudy (anonymous):

one more

OpenStudy (anonymous):

idk is it a varible?

OpenStudy (anonymous):

2x^2

OpenStudy (anonymous):

oh ok i see now

OpenStudy (anonymous):

−2x3 + 6x2 2x^2(-x +6) or -2x^2(x-6)

OpenStudy (anonymous):

do you get it

OpenStudy (anonymous):

not really;/

OpenStudy (anonymous):

lets say you have \[5x^{7}+25x^{4}\] most common between them \[5x^{4}\] \[5x^{4}(x^{3}+5)\]

OpenStudy (anonymous):

ok i see how that is working

OpenStudy (anonymous):

or you can do it this way \[−2x^{3} + 6x^{2} \] 2 is a factor \[2(−x^{3} + 3x^{2}) \] ask yourself can i factor more yes it looks like i can get x more \[2x(−x^{2} + 3x^{1}) \] ask yourself can i factor more yes it looks like i can get x more \[2x^{2}(−x^{1} + 3) \] ask yourself can i factor more no

OpenStudy (anonymous):

oh ok i see how u did that now

OpenStudy (anonymous):

thank you

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