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derive with product rule
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\[(x ^{2} - \sqrt{x}) 3^{x}\]
Do You Know What The Product Rule Is ?
@swin2013
yep
Did You try To Solve It ? @swin2013
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yep \[(x ^{2} - \sqrt{x})(\ln 3) 3^{x} + (2x - 1/2x ^{1/2}) 3^{x} \] that's what i got so far
Well You Are Doing It Right, Whats The Problem ?
factoring it
\[(x^2-\sqrt{x})(\ln3)3^x+(2x-\frac{ 1 }{ 2\sqrt{x}})3^x\]
\[3^x[(x^2-\sqrt{x})(\ln3)+(2x-\frac{ 1 }{ 2\sqrt{x}}]\]
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nvm, i see it.
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