Question

(2y^2-y+6)-2(y^2-3y+5)=11
step by step please.

Answer 1

I got 3, is this correct?

Answer 2

3 is correct. Do you still need step by step?

Answer 3

\[2y ^{2}-y+6-2y ^{2}+6y-10=11\]
you need to combine like terms and eliminate the ones that cancel out.
so you get....
5y-4=11
add 4 to both sides
5y=15
Divide by 5
y=3

Answer 4

Thank you.