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If g(x)+x sin g(x)=x^2 and g(1)=0, find g′(1).
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g(1) = 0 ?? Then g(1) + x sin g(1) = 1^2 0 + 1 sin 0 = 1 0 = 1 Am I missing something here?
im looking for the derivative of g(1)
lol how i wished that was the question
what @zugzwang means is that probably there's a typo or ques is incorrect..
ahhh i see ya sorry i did type the question out incorrectly let me fix that
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