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OpenStudy (anonymous):
Simplify 10^1-x=6^x? The answer is x=1/log 6+1, i don't know how to get it.
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OpenStudy (anonymous):
Take logarithm on both sides ull get (1-x) log 10 = xlog 6
OpenStudy (anonymous):
So then do i divide each side by log 10? @him1618
OpenStudy (anonymous):
yes do that...and remmbr log 10 =1
OpenStudy (anonymous):
so 1-x =x log 6? @him1618
OpenStudy (anonymous):
yes
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