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^3√logx How to work out the derivative?
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\[\sqrt[3]{logx}\] This is the Math Notation.
\[Let ...f(x)=\sqrt[3]{x}.....and ....g(x)=\log(x)\] Now can u tell me the derivative of f(g(x))?
Hello...........
Using the chain rule now to work this out.
yes
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1/3x^2/3(logx)1/x(x) ?
\[\frac{ 1 }{ 3 }(\log x)^{\frac{ -2 }{ 3 }}{\times}\frac{ 1 }{ xln10 }\]
Where did log10 come from?
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