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Mathematics 16 Online
OpenStudy (anonymous):

find y'' of xy + y^2=1

OpenStudy (shubhamsrg):

did you find y' ?

OpenStudy (shubhamsrg):

or better, solve for y first,,the given eqn is a quadratic in y.

OpenStudy (anonymous):

is it 2?

OpenStudy (shubhamsrg):

i dont know! :P

OpenStudy (shubhamsrg):

i mean i know the method/concept..though am too lazy solving! :P

OpenStudy (anonymous):

can you explain the concept then?

OpenStudy (shubhamsrg):

y^2 + xy -1 = 0 solve for y from here in terms of x then differentiate twice..

OpenStudy (shubhamsrg):

did i explain well ?

OpenStudy (anonymous):

yeah! thanks :)

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