Question

Find the first six terms of the sequence.

a1 = 6, an = 2 • an-1

6, 12, 14, 16, 18, 20

12, 24, 48, 96, 192, 384

0, 2, 12, 14, 16, 18

6, 12, 24, 48, 96, 192

Answer 1

its the same as the previous one, try it

n = 2 what do you get?

Answer 2

im so confused... @surdawi

Answer 3

\[a_{n}=2*a_{n-1}\]
plug n = 2
and write it down then i will help ypu

Answer 4

a2=2*a2-1 @surdawi

Answer 5

2-1=?

Answer 6

1

Answer 7

@surdawi

Answer 8

so is it \[a_{1}\]?

Answer 9

a2=2*a1-1 ?? @surdawi

Answer 10

no i mean what is the value of it

Answer 11

of a1? @surdawi

Answer 12

1

Answer 13

look at the question

Answer 14

your confusing me O.o @surdawi

Answer 15

a1 = 6
plug it in

Answer 16

a2=2*6-1

Answer 17

@surdawi

Answer 18

6-1?
\[a_{1}=6\]

Answer 19

5

Answer 20

@surdawi

Answer 21

2*6

Answer 22

12

Answer 23

now plug in
n = 3