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what is 2x^2 -7 +3=0??
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2x^2 -7 +3=0 2x^2 = 7 -3 2x^2 = 4 x^2 = 4/2 x = sqrt(2)
2(x^2-2) x= + or - sqrt(2)
2x^2-4=0 2x^2=4 x^2=4/2=2 x=under root2
ok @MusicTeacher
answer is \[\sqrt{2}\]
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ok ty but the answer is supposed to be 1/2
\[x^2-7+3=0\] is it your question?
@MusicTeacher
no its \[\pm \sqrt{2}\]
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