Question

Find the vertex for the equation:

y = 3x2 + 18x + 30


(-3, 3)
(-3, -51)
(3, 111)

Answer 1

If your quadratic equation is of the form
\[y = ax^{2} + bx + c\]
Then the x=value of your vertex is given by the formula
\[-\frac{b}{2a}\]

Answer 2

And to find the y-value, either you plug in what you got for the x-value, or follow this formula
\[\frac{4ac-b^{2}}{4a}\]

Answer 3

ok thanks, I see!!