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How do you write the inverse of f(x) = 3x - 1 f -1(x)
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In inverses, the \(\rm x\) becomes \(\rm y\).\[\rm x = 3y - 1\]Solve for \(\rm y\)
replace x with y and put it equal to x x= 3y-1 solve for y that is the inverse
So would it be log3x- 1?
no
I'm not use to this kind I'm use to the one's that already have log in it so what's different in finding these ones?
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