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OpenStudy (immings):
Cosx +SinxTanx = 1/Cosx CosX +Sinx(Sinx / Cosx) = 1 / CosX What can I do next? Cosx + Sin^2 x / Cosx = 1/Cosx??
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OpenStudy (anonymous):
by taking lcm (cosx*cosx+sin^2x)/cosx=1/cosx cos^2x+sin^2x=cosx/cosx 1=1
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