3^{x+3}-9^{2x-1}=0
what are the steps to finding the solution?
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OpenStudy (kamille):
firstly, you need to change 9 to 3^2
OpenStudy (kamille):
What will you get?
OpenStudy (anonymous):
3^{x+3} = 3^2^{2x-1}=0
OpenStudy (anonymous):
ignore = 0
OpenStudy (campbell_st):
rewrite the equation in terms of base 3
and then equate the 2 terms
\[3^{x + 3}= 3^{2(2x - 1)}\]
now they are the same, just solve
x + 3 = 2(2x -1)
for x.
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OpenStudy (kamille):
So, now you can say that x+3=2(2x+1) and you need to find x now
OpenStudy (anonymous):
how do i solve for x
OpenStudy (kamille):
x+3=4x+2 now you need to movie all numbers which have x to left, and all numbers which don't have x to the right. try it.
OpenStudy (anonymous):
cause its -1 not +1 it looks like x+3=4x+2 then 5x=-1??
OpenStudy (kamille):
Oh,sorry, my bad.
x+3=2(2x-1)
x+3=4x-2
-3x=-5|:(-3)
x=1 2/3
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OpenStudy (anonymous):
5|:(-3)???
OpenStudy (anonymous):
how does x = 12/3?
OpenStudy (anonymous):
x should equal 1.667 cause (-5)/(-3)
myininaya (myininaya):
He wrote it as a mixed fraction.
Also in the future, please don't post the same question twice. You should either bump or get more eyes by posting a link to your question in the math chat.
Thanks.