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Evaluate (ab)2 for a = 4 and b = 3.
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Is that "(ab) times 2" or \[(ab)^{2}\]
simply replace a with 4 and b with 3 in the given expression
isnt that just like 86
given that (ab)2 where a =4 and b= 3 (4*3)2= (12)2 = 24
still wooda done it my way
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yeah thanks yall
if your way gave you 86, then it is wrong.
if it is really (ab)^2, then both 24 and 86 are wrong... ( (4)(3) )^2 = 12^2 = 144
Assuming he posted the original question correctly.
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