please help! in desperate need of help and need to get it done!!! best answer:)

The next paragraph is an explanation of why this construction creates an equilateral triangle. Write the explanation in your own words.
And since the point A is the center of the circle CDB, AC is equal to AB [Def. 1.15]. Again, since the point B is the center of the circle CAE, BC is equal to BA [Def. 1.15]. But CA was also shown (to be) equal to AB. Thus, CA and CB are each equal to AB. But things equal to the same thing are also equal to one another [C.N.1]. Thus, CA is also equal to CB. Thus, the three (straight-lines) CA, AB, and BC are equal to one another.

Question

please help! in desperate need of help and need to get it done!!! best answer:)

The next paragraph is an explanation of why this construction creates an equilateral triangle.  Write the explanation in your own words.
And since the point A is the center of the circle CDB, AC is equal to AB [Def. 1.15].  Again, since the point B is the center of the circle CAE, BC is equal to BA [Def. 1.15].  But CA was also shown (to be) equal to AB.  Thus, CA and CB are each equal to AB.  But things equal to the same thing are also equal to one another [C.N.1].  Thus, CA is also equal to CB.  Thus, the three (straight-lines) CA, AB, and BC are equal to one another.

anonymous · Answer

here is the picture that goes with it

anonymous · Answer

since AB and AC are radii of the same circle CDB, they are equal. Again, since AB and BC are radii of same circle CAE, they are equal. Thus, by transition property of equality, AB=AC=BC. Thus ABC is an equilateral triangle.