Question

Need help on solving three system of equations using substitution?

-x-y-z=-9
-5x+5y+6z=8
3x+3z=5

I really need help...

Answer 1

This is confusing....

Answer 2

Somebody please help me...

Answer 3

x-y-z=-9
z = -9 -x + y
Using this:
3x+3z=5
3x + 3(-9 -x +y) = 5
3x -27 -3x +3y = 5
3y - 27 = 5
3y = 32
y = 32/3

x - 32/3 - (-9 - x + 32/3) = -9
x - 32/3 + 9 + x - 32/3 = -9
2x - 12.3 = -9
2x = 3.3
x = 1 2/3

z = -9 - 1 2/3 + 32/3
z = 0


1 2/3 - 32/3 - 0 = -9

Answer 4

Thanks for helping

Answer 5

R u sure these how you do them

Answer 6

Best Response 0
x-y-z=-9
z = -9 -x + y
Using this:
3x+3z=5
3x + 3(-9 -x +y) = 5
3x -27 -3x +3y = 5
3y - 27 = 5
3y = 32
y = 32/3

x - 32/3 - (-9 - x + 32/3) = -9
x - 32/3 + 9 + x - 32/3 = -9
2x - 12.3 = -9
2x = 3.3
x = 1 2/3

z = -9 - 1 2/3 + 32/3
z = 0


1 2/3 - 32/3 - 0 = -9

Answer 7

Thanks

Answer 8

welcome

Answer 9

That was quick

Answer 10

yep

Answer 11

Can you add her people as friends

Answer 12

here

Answer 13

who you talking about

Answer 14

Oh nothing..never mind

Answer 15

oh ok

Answer 16

How did you get 12.3