Question

Limits

Answer 1

my factors arent cancelling out

Answer 2

\[\lim_{x \rightarrow -3}\frac{ x^2+5x+6 }{ x^2-x-12 }\]

Answer 3

then you factored wrong...

Answer 4

\[= \lim_{x \rightarrow -3} \frac{(x+3)(x+2)}{(x-4)(x+3)}=\lim_{x \rightarrow -3}\frac{x+2}{x-4}=1/7\]

Answer 5

im getting this but ot sure how ? \[\lim_{x \rightarrow -2}\frac{ x^2+2x+3x+6 }{ x^2-3x+4x-12 }\]