Question

t(7t+4)=0

(fractions and and itegers)

Answer 1

t(7t+4)=0
7t^2+4t = 0
a = 7, b = 4 , c=0;

t = (-b+- sqrt(b^2 - 4.a.c))/2a
t= (-4+- sqrt(16 -0))/14
t = (-4 +- 4)/14

for (+)
t =(-4+4)/14 = 0

for (-)
t=(-4-4)/14 = -8/14 = -4/7

so t =0 or -4/7